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Build Information

Failed to build FlexiJSONCoder with Swift 5.10 for iOS using Xcode 15.4.

Build Command

Build command unavailable

Build Log

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RunAll
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Builder version: 4.58.5
Interrupt handler set up.
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Checkout
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Clone URL: https://github.com/Forgwhiz/FlexiJSONCoder.git
Reference: main
Initialized empty Git repository in /Users/admin/builder/spi-builder-workspace/.git/
From https://github.com/Forgwhiz/FlexiJSONCoder
 * branch            main       -> FETCH_HEAD
 * [new branch]      main       -> origin/main
HEAD is now at 99a950a Update README.md
Cloned https://github.com/Forgwhiz/FlexiJSONCoder.git
Revision (git rev-parse @):
99a950a73664ceb1e8a0cf2beea1facc424a0c42
SUCCESS checkout https://github.com/Forgwhiz/FlexiJSONCoder.git at main
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Build
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Selected platform:         iOS
Swift version:             5.10
Building package at path:  $PWD
https://github.com/Forgwhiz/FlexiJSONCoder.git
Command line invocation:
    /Applications/Xcode-15.4.0.app/Contents/Developer/usr/bin/xcodebuild -IDEClonedSourcePackagesDirPathOverride=/Users/admin/builder/spi-builder-workspace/.dependencies -resolvePackageDependencies
User defaults from command line:
    IDEClonedSourcePackagesDirPathOverride = /Users/admin/builder/spi-builder-workspace/.dependencies
    IDEPackageSupportUseBuiltinSCM = YES
2024-12-11 10:56:03.322 xcodebuild[461:2530] Writing error result bundle to /var/folders/fs/0w3t9t1d28xc3bj0tgb8hcrw0000gn/T/ResultBundle_2024-11-12_10-56-0003.xcresult
xcodebuild: error: Unable to read project 'FlexiJSONCoder.xcodeproj'.
	Reason: The project ‘FlexiJSONCoder’ cannot be opened because it is in a future Xcode project file format (77). Adjust the project format using a compatible version of Xcode to allow it to be opened by this version of Xcode.
GENERIC FAILURE 5.10 iOS